Stress potentials for anisotropic metal plasticity

The metal plasticity models in Abaqus use the Mises stress potential for isotropic behavior and the Hill stress potentials for anisotropic behavior. Both of these potentials depend only on the deviatoric stress, so the plastic part of the response is incompressible. This means that, in cases where the plastic flow dominates the response (such as limit load calculations or metal forming problems), except for plane stress problems, the finite elements should be chosen so that they can accommodate the incompressible flow. Usually the reduced integration elements are used for this purpose: in Abaqus/Standard the “hybrid” elements can also be used, at higher cost. The fully integrated first-order continuum elements in Abaqus/Standard use selectively reduced integration, whereby the volumetric strain is calculated at the centroid of the element only. Those elements, which are described in Solid isoparametric quadrilaterals and hexahedra, are also suitable for such problems.

See Also
In Other Guides
Hill Anisotropic Yield/Creep

ProductsAbaqus/StandardAbaqus/Explicit

The Mises stress potential is

f(σ)=q,

where

q=32S:S,

in which S is the deviatoric stress:

S=σ-13trace(σ)I=σ-13II:(σ).

The potential is a circle in the plane normal to the hydrostatic axis in principal stress space. For this function,

fσ=1q32S,

and

2fσσ=1q(32-12II-fσfσ)

in which is the fourth-order unit tensor.

Hill's stress function is a simple extension of the Mises function to allow anisotropic behavior. The function is

f(σ)=F(σy-σz)2+G(σz-σx)2+H(σx-σy)2+2Lτyz2+2Mτzx2+2Nτxy2,

in terms of rectangular Cartesian stress components, where F,G,H,L,M,N are constants obtained by tests of the material in different orientations. They are defined as

F=σ022(1σ¯222+1σ¯332-1σ¯112),
G=σ022(1σ¯332+1σ¯112-1σ¯222),
H=σ022(1σ¯112+1σ¯222-1σ¯332),
L=32(τ0τ¯23)2,
M=32(τ0τ¯13)2,
N=32(τ0τ¯12)2,

where σ0,σ¯11,σ¯22,σ¯33,τ¯12,τ¯23,τ¯13 are specified by the user and τ0=σ0/3. σ¯ and τ¯ are the values of stress that make the potential equal to σ0 if only one stress component is nonzero.

For this function

fσ=1fb,

where

b=[-G(σz-σx)+H(σx-σy)F(σy-σz)-H(σx-σy)-F(σy-σz)+G(σz-σx)2Nτxy2Mτzx2Lτyz].

In addition,

2fσσ=1f(bσ-1f2bb),

where

bσ=[G+H-H-G000-HF+H-F000-G-FF+G0000002N0000002M0000002L].